Function IGetLeaderInfo( _
   ByRef PointCount As Integer _
) As Double

Dim instance As INote
Dim PointCount As Integer
Dim value As Double
 
value = instance.IGetLeaderInfo(PointCount)

double IGetLeaderInfo( 
   out int PointCount
)

double IGetLeaderInfo( 
&   [Out] int PointCount
) 

Parameters

PointCount

Number of points

Return Value

• in-process, unmanaged C++: Pointer to an array of doubles (see Remarks)
• VBA, VB.NET, C#, and C++/CLI: Not supported

See In-process Methods for details about this type of method.

There can be 0, 1, or 2 lines used with the leader line. If the note is not attached, then there are 0 lines;  otherwise, you have a straight leaderline (1 line) or a bent leaderline (2 lines). You must infer the number of leader lines based on IsAttached() and HasExtraLeader().

• IsAttached() == false implies no leaderline and  no leaderline points (PointCount=0).

• HasExtraLeader() == false implies a straight leaderline and1 line (PointCount=2)

• HasExtraLeader() == True implies a bent leaderline and 2 lines (PointCount=3)

Format of return information is the following array of doubles:

• return value[0] = x coordinate of first leader point

• return value[1] = y coordinate  of first leader point

• return value[2] = z coordinate  of first leader point
   

• return value[3] = x coordinate  of second leader point

• return value[4] = y coordinate  of second leader point

• return value[5] = z coordinate  of second leader point
   

• return value[6] = x coordinate  of third leader point

• return value[7] = y coordinate  of third leader point

• return value[8] = z coordinate  of third leader point