Description
A long column consists of two portions each with a constant cross section. Both cross sections are squares with sides 1" and 0.795" with the thicker portion in the bottom. The thicker portion is fixed at its base and a force of 100 lbs is applied to the free end of the thinner portion. The lengths of the thicker and thinner portions are 60" and 40" respectively. Calculate the buckling load of the column.

File Name
Browse to drive
letter:\Users\Public\Public Documents\SOLIDWORKS\SOLIDWORKS
version\samples\Simulation
Examples\Verification\Buckling_5.SLDPRT and open the
file.
Mesh Type
Solid mesh and Beam mesh in separate studies.
Material Properties
Modulus of elasticity = 3X107 psi, Poisson's ratio = 0.3.
Results
|
Critical (Buckling) Load
|
Theory
|
530.00 |
SOLIDWORKS Simulation - Solid Mesh |
531.62 |
SOLIDWORKS Simulation - Beam Mesh |
534.96 |
The buckling load is calculated as: P
cr = 2.12 EI
2/L
2, where:
- Pcr = Critical (buckling) force
- E = Modulus of elasticity
- I2 = Moment of inertia of the cross section of the thicker portion of the column
- L = Total length of the column
The critical load from SOLIDWORKS Simulation
is calculated as:
Pcr = (Applied force)*(Buckling load factor)
Reference
Wang, C. T., “Applied Elasticity,” McGRaw-Hill Book Company, New York, 1953, pp 231.